Isolation Score $$s(x,n) = 2*{-\frac{E(h(x))}{c(n)}}$$ Where $h(x)$=path length of instance x $E[h(x)]$ = average path length across all Isolation Trees $c(n)$ = normalization value based on sample size n
Isolation Score $$s(x,n) = 2*{-\frac{E(h(x))}{c(n)}}$$ Where $h(x)$=path length of instance x $E[h(x)]$ = average path length across all Isolation Trees $c(n)$ = normalization value based on sample size n